6k^2+12k=210

Solution for 6k^2+12k=210 equation:

6k^2+12k=210

We move all terms to the left:

6k^2+12k-(210)=0

a = 6; b = 12; c = -210;
Δ = b2-4ac
Δ = 122-4·6·(-210)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-72}{2*6}=\frac{-84}{12}
=-7
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+72}{2*6}=\frac{60}{12}
=5
$